Assume that Alice and Bob have RSA key pairs (EA, DA), and (EB, DB), where E is the encryption key (= algorithm) and D is the decryption key.
Here is a table of "exponentials" with base 03. The entry E(rs) is the field element given by 03rs, where these are hex numbers, and the initial ``0x'' is left off for simplicity.
Table of ``exponentials'': E(rs) = 03^rs | |||||||||||||||||
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
E(rs) | s | ||||||||||||||||
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | a | b | c | d | e | f | ||
r | |||||||||||||||||
0 | 01 | 03 | 05 | 0f | 11 | 33 | 55 | ff | 1a | 2e | 72 | 96 | a1 | f8 | 13 | 35 | |
1 | 5f | e1 | 38 | 48 | d8 | 73 | 95 | a4 | f7 | 02 | 06 | 0a | 1e | 22 | 66 | aa | |
2 | e5 | 34 | 5c | e4 | 37 | 59 | eb | 26 | 6a | be | d9 | 70 | 90 | ab | e6 | 31 | |
3 | 53 | f5 | 04 | 0c | 14 | 3c | 44 | cc | 4f | d1 | 68 | b8 | d3 | 6e | b2 | cd | |
4 | 4c | d4 | 67 | a9 | e0 | 3b | 4d | d7 | 62 | a6 | f1 | 08 | 18 | 28 | 78 | 88 | |
5 | 83 | 9e | b9 | d0 | 6b | bd | dc | 7f | 81 | 98 | b3 | ce | 49 | db | 76 | 9a | |
6 | b5 | c4 | 57 | f9 | 10 | 30 | 50 | f0 | 0b | 1d | 27 | 69 | bb | d6 | 61 | a3 | |
7 | fe | 19 | 2b | 7d | 87 | 92 | ad | ec | 2f | 71 | 93 | ae | e9 | 20 | 60 | a0 | |
8 | fb | 16 | 3a | 4e | d2 | 6d | b7 | c2 | 5d | e7 | 32 | 56 | fa | 15 | 3f | 41 | |
9 | c3 | 5e | e2 | 3d | 47 | c9 | 40 | c0 | 5b | ed | 2c | 74 | 9c | bf | da | 75 | |
a | 9f | ba | d5 | 64 | ac | ef | 2a | 7e | 82 | 9d | bc | df | 7a | 8e | 89 | 80 | |
b | 9b | b6 | c1 | 58 | e8 | 23 | 65 | af | ea | 25 | 6f | b1 | c8 | 43 | c5 | 54 | |
c | fc | 1f | 21 | 63 | a5 | f4 | 07 | 09 | 1b | 2d | 77 | 99 | b0 | cb | 46 | ca | |
d | 45 | cf | 4a | de | 79 | 8b | 86 | 91 | a8 | e3 | 3e | 42 | c6 | 51 | f3 | 0e | |
e | 12 | 36 | 5a | ee | 29 | 7b | 8d | 8c | 8f | 8a | 85 | 94 | a7 | f2 | 0d | 17 | |
f | 39 | 4b | dd | 7c | 84 | 97 | a2 | fd | 1c | 24 | 6c | b4 | c7 | 52 | f6 | 01 |
Similarly, here is a table of ``logarithms'', where the entry L(rs) is the field element that satisfies rs = 03L(rs), where these are hex numbers, and again the initial ``0x'' is left off.
Table of ``logarithms'': rs = 03^L(rs) | |||||||||||||||||
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
L(rs) | s | ||||||||||||||||
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | a | b | c | d | e | f | ||
r | |||||||||||||||||
0 | 00 | 19 | 01 | 32 | 02 | 1a | c6 | 4b | c7 | 1b | 68 | 33 | ee | df | 03 | ||
1 | 64 | 04 | e0 | 0e | 34 | 8d | 81 | ef | 4c | 71 | 08 | c8 | f8 | 69 | 1c | c1 | |
2 | 7d | c2 | 1d | b5 | f9 | b9 | 27 | 6a | 4d | e4 | a6 | 72 | 9a | c9 | 09 | 78 | |
3 | 65 | 2f | 8a | 05 | 21 | 0f | e1 | 24 | 12 | f0 | 82 | 45 | 35 | 93 | da | 8e | |
4 | 96 | 8f | db | bd | 36 | d0 | ce | 94 | 13 | 5c | d2 | f1 | 40 | 46 | 83 | 38 | |
5 | 66 | dd | fd | 30 | bf | 06 | 8b | 62 | b3 | 25 | e2 | 98 | 22 | 88 | 91 | 10 | |
6 | 7e | 6e | 48 | c3 | a3 | b6 | 1e | 42 | 3a | 6b | 28 | 54 | fa | 85 | 3d | ba | |
7 | 2b | 79 | 0a | 15 | 9b | 9f | 5e | ca | 4e | d4 | ac | e5 | f3 | 73 | a7 | 57 | |
8 | af | 58 | a8 | 50 | f4 | ea | d6 | 74 | 4f | ae | e9 | d5 | e7 | e6 | ad | e8 | |
9 | 2c | d7 | 75 | 7a | eb | 16 | 0b | f5 | 59 | cb | 5f | b0 | 9c | a9 | 51 | a0 | |
a | 7f | 0c | f6 | 6f | 17 | c4 | 49 | ec | d8 | 43 | 1f | 2d | a4 | 76 | 7b | b7 | |
b | cc | bb | 3e | 5a | fb | 60 | b1 | 86 | 3b | 52 | a1 | 6c | aa | 55 | 29 | 9d | |
c | 97 | b2 | 87 | 90 | 61 | be | dc | fc | bc | 95 | cf | cd | 37 | 3f | 5b | d1 | |
d | 53 | 39 | 84 | 3c | 41 | a2 | 6d | 47 | 14 | 2a | 9e | 5d | 56 | f2 | d3 | ab | |
e | 44 | 11 | 92 | d9 | 23 | 20 | 2e | 89 | b4 | 7c | b8 | 26 | 77 | 99 | e3 | a5 | |
f | 67 | 4a | ed | de | c5 | 31 | fe | 18 | 0d | 63 | 8c | 80 | c0 | f7 | 70 | 07 |
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Note: the random RA and RB are secret and used only once.
Note: A and B can convince one another that they share the same secret S, but if B doesn't know A's secret, it will not be revealed.