For this laboratory, you are to experiment with the bit pattern used to represent an int in computers that use 2's complement to represent 32-bit integers. (See text, Section 4.2, pages 210-220. In C/C++ on Sun hardware the int type is a 32-bit 2's complement signed integer.)

Given either an "ordinary" integer (in decimal) or a bit pattern, it is easy to get the other representation, say, with a simple program like the following in C. (A similar program in Java is here.)

#include <stdio.h>
#include <ctype.h>
void main(void){
   int i;
   char ch;
   for( ; ; ) {
      while (isspace(ch = getchar()))
         ;
      if (ch == 'x') {
         scanf("%x", &i);
         printf("  Decimal: %10i\n", i);
         printf("  Bits: %08x \n", i);
      }
      else if (ch == 'i') {
         scanf("%i", &i);
         printf("  Decimal: %10i\n", i);
         printf("  Bits: %08x \n", i);
      }
      else break;
   }
}

i 47
  Decimal:         47
  Bits: 0000002f 
i -3
  Decimal:         -3
  Bits: fffffffd 
x ffffffff
  Decimal:         -1
  Bits: ffffffff 
q

1. Convert 189 to:
   a) An unsigned binary number
   b) A 16-bit two's complement number
   

2. Convert -189 to:
   a) A 16-bit two's complement number
   

3. Convert binary number 10011111001 to:
   a) octal
   b) hexadecimal
   c) decimal
   

4. Perform the following binary addition:
   10000111 + 10111011
   

5. Convert the hexadecimal number AB32 to:
   a) binary
   b) octal
   c) decimal
   

1. a) 10111101
   b) 0000000010111101
2. b) 1111111101000011
3. a) 2371
   b) 4F9
   c) 1273
   
4. 101000010
5. a) 1010 1011 0011 0010
   b) 125462
   c) 43,826

Base conversions in C: here.

Base conversions in Java: here.